Math Paper

Derp college Derp derpington Human Resource Management Research Paper is Business Mathematics 101 first Tri Semester SY 2011-2012 Ms. derpina derp TABLE OF CONTENTS TITLE PAGE ACKNOWLEDGEMENTii TOPICS Simple Discount1 Simple Interest2 Four kinds of Interest available3 Compounded Amount and Compound Interest4 Linear Programming Problems * Maximization6 * Minimization8 Forecasting by Trend Projection10 Acknowledgment I might want to say thanks to God for directing and giving me inspiration to do this math look into paper; my companions for responding to my inquiries regarding this paper; Dr. Masajo for allowing me the chance to acquire information; and my mom to continually remind me to improve in school. I might want to thank my coach, Ms. Effortlessness Chong, for being my guide and to help me in my school life. Straightforward Discount Find the current estimation of $3800 due in a half year at 7% markdown rate. A) F = $3800 d = 7% = . 07 t = 6/12 = 1/2 Formula: D = Fdt Solution: D = $3800 (. 07) (1/2) D = $133 P = F †D P = $3800 †$133 P = $3667 Discount $2056. 80 for 85 days at a rebate pace of 6 ? % B) F = 2056. 80 d = 6 ? % = . 065 t = 85/360 = 17/72 years Formula: D = Fdt Solution: D = $2056. 80 (. 065) (17/72) D = $31. 57 P = F †D P = $2056. 80 †$31. 57 P = $2025. 13 Simple Interest Find basic enthusiasm on $10,000 at the pace of 5% for a long time. Likewise discover the sum for a long time. A) P = $10,000 R = 5% = . 05 T = 5 years = n = 5 I = PRT I = $10,000 (. 05) (5) I = $2500 A = P + I A = $10,000 + $2500 A = $12,500 Find straightforward enthusiasm on $15,600 for 1 ? a long time at the pace of 8% per annum. Likewise discover aggregate sum. B) P = $15,600 R = 8% = . 08 T = 1 ? = n = 1 ? I = PRT I = $15,600 (. 08) (1? ) I = $1872 A = P + I A = $15,600 + $1872 A = $17472 4 Types of Interest Available Locate the diverse enthusiasm on $1000 at 6% from June 23 2011 to September 21 2015. An) Approximate number of days: Year: 2015 †2011 = 4 Month: 8 †6 = 2 Days: 51 †23 = 28 4 x 360 = 1440 2 x 30 = 60 28 = 28 = 1528 Days B) Actual Number of days: 4 years x 365 days = 1463 days January 30 †June 23 = 173 days January 30 †September 21 = 263 days 1463 Days †173 days = 1287 days 1287 Days + 263 days = 1550 days = 1550 days C) Io enthusiasm for surmised number of days: Io = PRT = $1000 (. 06) (1528/360) Io = $254. 67 D) Ie enthusiasm for estimated number of days: Ie = PRT = $1000 (. 06) (1528/365) Ie = $251. 8 E) Io enthusiasm for real number of days: Io = PRT = $1000 (. 06) (1550/360) Io = $258. 33 F) Ie Interest for real number of days: Ie = PRT = $1000 (. 06) (1528/365) Ie = $254. 79 Compounded sum and Compounded intrigue Find the Compounded sum and intensified enthusiasm of $1000 at 7% for a long time A) B) Compounded Annually P = $1000 R = 7% = . 07 T = 3 y ears = N = 3 x 1 = 3 A = P (1+i) ^ n A = $1000 (1+0. 7) ^ 3 A = $1225. 043 I = A †P I = $1225. 043 †$1000 I = $225. 043 C) Compounded Semi †Annually P = $1000 R = 7/2 % = 3. 5 = . 035 T = 3 years = N = 3 x 2 = 6 A = P (1+i) ^ n A = $1000 (1+0. 5) ^ 6 A = $1229. 36 I = A †P I = $1229. 36 †$1000 I = $229. 36 D) Compounded Quarterly P = $1000 R = 7/4% = 1. 75 = . 0175 T = 3 years = N = 3 x 4 = 12 A = P (1+i) ^ n A = $1000 (1+0. 175) ^ 12 A = $1231. 44 I = A †P I = $1231. 44 †$1000 I = $231. 44 E) Compounded Monthly P = $1000 R = 7/12% = . 5833 = . 00583 T = 3 years = N = 3 x 12 = 36 A = P (1+i) ^ n A = $1000 (1+. 00583) ^ 36 A = $1232. 78 I = A †P I = $1232. 78 †$1000 I = $232. 78 Compounded sum and Compounded intrigue Find the Compounded sum and intensified enthusiasm of $1500 at 5% for a long time A) B) Compounded Annually P = $1500 R = 5% = . 05 T = 3 years = N = 3 x 1 = 3 A = P (1+i) ^ n A = $1500 (1+. 05) ^ 3 A = $1736. 4375 I = A †P I = $1736. 4375 †$1500 I = $236. 4375 C) Compounded Semi †Annually P = $1500 R = 5/2 % = 2. 5 = . 025 T = 3 years = N = 3 x 2 = 6 A = P (1+i) ^ n A = $1500 (1+. 025) ^ 6 A = $1739. 540127 I = A †P I = $1739. 540127 †$1500 I = $739. 540127 D) Compounded Quarterly P = $1500 R = 5/4% = 1. 25 = . 0125 T = 3 years = N = 3 x 4 = 12 A = P (1+i) ^ n A = $1500 (1+. 0125) ^ 12 A = $1741. 131777 I = A †P I = $1741. 131777 †$1500 I = $741. 131777 E) Compounded Monthly P = $1500 R = 5/12% = . 41666 = . 00416 T = 3 years = N = 3 x 12 = 36 A = P (1+i) ^ n A = $1500 (1+. 00416) ^ 36 A = $1741. 792 I = A †P I = $1741. 792 †$1500 I = $741. 792 Linear Programming Problems (Maximization) Levi’s Jeans producing organization purchase2 styles of pants, style X and style Y, which sell for $90 and $75 properly. Unit creation test for style X is $40 and for style Y $35. Crude materials accessible month to month are 90 meters while preparing time at a maximum of 70 hours out of every week. Style X pants made 3 meters of materials and 2 for preparing them. For style Y, 2 meters and 2 for handling. Style X showcase request is close to 40 every week. What number of each style ought to be created in every week so as to make benefit most extreme? | Style X| Style Y| Total Available| RM| 3| 2| 90| PT| 2| 70| MD| 40| | Style X| Style Y| USP| $90| $75| UPE| 40| 35| UBM| $50| $40| Composition of straight programming issues: I. Choice Variable X = Number of style X to be created week by week Y = Number of style Y to be delivered week by week II. Target Function Maximum Profit (Z): Z = $50X+$40Y III. Subjects and Constraints: RM = 3X+2Y < 90PT = 2X+2Y < 70 MD = X < 40X; Y > 0 IV. Graphical Solutions A) By block B) Graphical introductions and focuses A crossing point between 2 lines C) Testing the bend of the raised polygon framed structure the target work V. Choice Raw Materials: 3X+2Y < 90 X = 30 Y = 45 Processing Time: 2X+2Y < 70 X = 35 Y = 35 Market Demand: X = 40 A) Z = $50X + $40Y = $50(0) + $40(35) =$1400 B) Z = $50X + $40Y = $50(20) + $40(75) =$1600 C) Z = $50X + $40Y = $50(30) + $40(0) =$1500 Choose B. Choice: The Levi’s fabricating organization must create 20 bits of style X and 50 bits of style Y to have a most extreme benefit of $1600. Straight Programming Problems (Minimization) Mrs. Smith mining organization possesses two mines evaluating metals reviewed into 3 classes. High evaluation (H), Medium evaluation (M) and second rate (L). The organization is attached with an agreement to furnish a refining plant with 12 tons of (H), 8 tons of (M), and 24 tons of (L) every week. It costs $2000 every day to run mine 1 and $1600 every day to run mine 2. In a day activity, Mine 1 produces 6 tons of (H), 2 tons of (M) and 4 tons of (L). While mine 2 produces 2 tons of (H); 2 tons of (M) and 12 tons of (L). How long seven days should every mine activity to satisfy company’s duty most monetarily? | Mine 1| Mine 2| Total Available| H| 6| 2| 12| M| 2| 8| L| 4| 12| 24| Cost| $2000| $1600| | I. Choice Variables: X = Number of days to run mine 1 Y = Number of days to run mine 2 II. Target Functions: Minimum Cost = $2000X + $1600Y III. Subjects to Constraints: H = 6X + 2Y > 12 M = 2X + 2Y > 8 L = 4X + 12Y > 24 X; Y < 0 IV. Graphical Solutions H = 6X + 2Y > 12M = 2X + 2Y > 8L = 4X + 12Y > 24 X = 2 Y = 6X = 4 Y = 4X = 6 Y = 2 P1 (0,6) Min C = $2000(0) + $1600(6) = $9600 P2 (1,3) Min C = $2000(1) + $1600(3) = $6800 P3 (3,1) Min C = $2000(3) + $1600(1) = $7600 P4 (6,0) Min C = $2000(6) + $1600(0) = $12000 Pick P2 V. Choice: Mrs. Smith’s mining organization should run dig 1 for 1 day and Mine 2 for 3 days so as to have a base expense of $6800. Determining by Trend Projection Forecast and chart the creation of rice in the Philippines for the years 2012 and 2015 of the yearly creation of rice from year 2000 to year 2010. Year (N)| Production of Rice (Y)| X| XY| Y’| X^2| 2000| 20| 0| | 0| 2001| 22| 1| 22| | 1| 2002| 18| 2| 36| | 4| 2003| 19| 3| 57| | 9| 2004| 21| 4| 84| | 16| 2005| 24| 5| 120| | 25| 2006| 22| 6| 132| | 36| 2007| 26| 7| 182| | 49| 2008| 28| 8| 224| | 64| 2009| 25| 9| 225| | 81| 010| 30| 10| 300| | 100| | ? (Y) = 255| ? (X) = 55| ? (XY)=1382| | ? (X^2) = 385| 2 Normal Equations: ?(Y) = NA + B? (X)Equation 1 ?(XY) = A? (X) + B? (X^2)Equation 2 Solve for B) 255 = 11A + 55B (- 5) 1382 = 55A + 385B - 1275 = - 55A †275B 1382 = 55A + 385B 107/100 = 110B/100 B = . 97272727 Solve for A) 255 = 11A + 55B 11A + 55B = 255 11A +55(. 97272727) = 255 11A + 53. 5 = 255 1 1 A = 255 †53. 5 11A/11 = 201. 5/11 A = 18. 31818182 A = 18. 32 B = 0. 97 Formula Y’ = A+Bx Year 2000 = 18. 32 + 0. 97(0) Y’ = 18. 32 Year 2001 = 18. 32 + 0. 97(1) Y’ = 19. 29 Year 2002 = 18. 32 + 0. 92(2) Y’ = 20. 6 Year 2003 = 21. 23 Year 2004 = 22. 2 Year 2005 = 23. 17 Year 2006 = 24. 14 Year 2007 = 25. 11 Year 2008 = 26. 08 Year 2009 = 27. 05 Year 2010 = 28. 02 In the table: Year (N)| Production of Rice (Y)| X| XY| Y’| X^2| 2000| 20| 0| 18. 32| 0| 2001| 22| 1| 22| 19. 29| 1| 2002| 18| 2| 36| 20. 26| 4| 2003| 19| 3| 57| 21. 23| 9| 2004| 21| 4| 84| 22. 2| 16| 2005| 24| 5| 120| 23. 17| 25| 2006| 22| 6| 132| 24. 14| 36| 2007| 26| 7| 182| 25. 11| 49| 2008| 28| 8| 224| 26. 08| 64| 2009| 25| 9| 225| 27. 05| 81| 2010| 30| 10| 300| 28. 02| 100| | ? (Y) = 255| ? (X) = 55| ? (XY)=1382| | ? (X^2) = 385|